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We want the standard enthalpy of formation for ca (oh)_2 Calculate moles of acid, calculate moles of base Thus, our required equation is the equation where all the constituent elements combine to form the compound, i.e.
The acid in excess is then titrated with n aoh (aq) of known concentration.we can thus get back to the concentration or molar quantity of m (oh)2.as it stands the question (and answer) are hypothetical. Nickel (ii)hydroxide may be formed without or (more likely. So this is a propanol derivative
Both names seem to be unambiguous.
The longer the alkyl chain attached to the hydroxyl head, usually the more basic the conjugate base is (and the less nucleophilic). 6.3072 g >>molarity = moles of solute/volume of solution (in litres) 0.45 m = n/0.4 l n = 0.45 m × 0.4 l = 0.18 mol you need 0.18 mol of nh_4oh molar mass of nh_4oh is 35.04 g/mol mass of solute = 0.18 cancelmol × 35.04 g/cancelmol = 6.3072 g Because n aoh → n a+ + oh − and n i2+ + 2oh −→n i(oh)2 total mols of n aoh 60ml ⋅ 0.45m ol/l = 27mm ol of n aoh (dont forget the m for milli=one thousandth) this will produce 27 2 = 13.5mm ol of n i(oh)2 now you multiply this by the molecular mass number to get the weight in milligrams (divide by 1000 to get the grams)
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