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I have a piece of code here that is supposed to return the least common element in a list of elements, ordered by commonality In order to instantiate, you need some realizations (implementations) of that interface. From collections import counter c = counte.

The first, [:], is creating a slice (normally often used for getting just part of a list), which happens to contain the entire list, and thus is effectively a copy of the list List is an interface, you cannot instantiate an interface, because interface is a convention, what methods should have your classes The second, list(), is using the actual list type constructor to create a new list which has contents equal to the first list.

Don't use quotes on the command line 1 don't use type=list, as it will return a list of lists this happens because under the hood argparse uses the value of type to coerce each individual given argument you your chosen type, not the aggregate of all arguments

You can use type=int (or whatever) to get a list of ints (or whatever) Let summarize the differences between list.of and arrays.aslist list.of can be best used when data set is less and unchanged, while arrays.aslist can be used best in case of large and dynamic data set. Given a dataframe, i want to groupby the first column and get second column as lists in rows, so that a dataframe like A b a 1 a 2 b 5 b 5 b 4 c 6 becomes a [1,2] b [5,5,4] c [6] how do i do this?

Is the a short syntax for joining a list of lists into a single list ( or iterator) in python For example i have a list as follows and i want to iterate over a,b and c. In c# if i have a list of type bool What is the fastest way to determine if the list contains a true value

I don’t need to know how many or where the true value is

I just need to know if one e. I can not find tge list of account passwords tgat i saved in google account I want to get a list of the column headers from a pandas dataframe The dataframe will come from user input, so i won't know how many columns there will be or what they will be called

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