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I have a piece of code here that is supposed to return the least common element in a list of elements, ordered by commonality 'list' exception is because k = list[0:j] sets k to be a slice of the list, which is logically another, often shorter, list. From collections import counter c = counte.

Let summarize the differences between list.of and arrays.aslist list.of can be best used when data set is less and unchanged, while arrays.aslist can be used best in case of large and dynamic data set. The reason you're getting the unhashable type List is an interface, you cannot instantiate an interface, because interface is a convention, what methods should have your classes

In order to instantiate, you need some realizations (implementations) of that interface.

The first, [:], is creating a slice (normally often used for getting just part of a list), which happens to contain the entire list, and thus is effectively a copy of the list The second, list(), is using the actual list type constructor to create a new list which has contents equal to the first list. Model status certified —models are expected to work with chromeos flex Minor issues expected —models are likely to support at least basic functionality, but are still being worked on by our team

You might run into minor issues Given a dataframe, i want to groupby the first column and get second column as lists in rows, so that a dataframe like A b a 1 a 2 b 5 b 5 b 4 c 6 becomes a [1,2] b [5,5,4] c [6] how do i do this? Here, append () is used to add items ( i.e integer version of string (i) in this program ) to the end of the list (b)

Int () is a function that helps to convert an integer in the form of string, back to its integer form.

Don't use quotes on the command line 1 don't use type=list, as it will return a list of lists this happens because under the hood argparse uses the value of type to coerce each individual given argument you your chosen type, not the aggregate of all arguments You can use type=int (or whatever) to get a list of ints (or whatever) A new list is created but the items in it are references to the orginal items (just like in the original list) Changes to the list itself are independent, but to the items will find the change in both lists.

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