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António manuel martins claims (@44:41 of his lecture "fonseca on signs") that the origin of what is now called the correspondence theory of truth, veritas est adæquatio rei et intellectus. Multiplying 0 by infinity is the equivalent of 0/0 which is undefined. The theorem that $\binom {n} {k} = \frac {n!} {k

Otherwise this would be restricted to $0 <k < n$ When you allow things like that in proofs you end up with nonsense like 1 = 0 A reason that we do define $0!$ to be $1$ is so that we can cover those edge cases with the same formula, instead of having to treat them separately

We treat binomial coefficients like $\binom {5} {6}$ separately already

Division is the inverse operation of multiplication, and subtraction is the inverse of addition Because of that, multiplication and division are actually one step done together from left to right The same goes for addition and subtraction Therefore, pemdas and bodmas are the same thing

To see why the difference in the order of the letters in pemdas and bodmas doesn't matter, consider the. HINT: You want that last expression to turn out to be $\big (1+2+\ldots+k+ (k+1)\big)^2$, so you want $ (k+1)^3$ to be equal to the difference $$\big (1+2+\ldots+k+ (k+1)\big)^2- (1+2+\ldots+k)^2\;.$$ That’s a difference of two squares, so you can factor it as $$ (k+1)\Big (2 (1+2+\ldots+k)+ (k+1)\Big)\;.\tag {1}$$ To show that $ (1)$ is just a fancy way of writing $ (k+1)^3$, you need to. Does anyone have a recommendation for a book to use for the self study of real analysis Several years ago when i completed about half a semester of real analysis i, the instructor used introducti.

Infinity times zero or zero times infinity is a battle of two giants

Zero is so small that it makes everyone vanish, but infinite is so huge that it makes everyone infinite after multiplication In particular, infinity is the same thing as 1 over 0, so zero times infinity is the same thing as zero over zero, which is an indeterminate form Your title says something else than. This answer is with basic induction method.when n=1, $\ 1^3-1 = 0 = 6.0$ is divided by 6. so when n=1,the answer is correct. we assume that when n=p , the answer is correct so we take, $\ p^3-p $ is divided by 6. then, when n= (p+1), $$\ (p+1)^3- (p+1) = (P^3+3p^2+3p+1)- (p+1)$$ $$\ =p^3-p+3p^2+3p+1-1 $$ $$\ = (p^3-p)+3p^2+3p $$ $$\ = (p^3-p)+3p (p+1) $$ as we assumed $\ (p^3-p) $ is.

Thank you for the answer, geoffrey 'are we sinners because we sin?' can be read as 'by reason of the fact that we sin, we are sinners' I think i can understand that But when it's connected with original sin, am i correct if i make the bold sentence become like this by reason of the fact that adam & eve sin, human (including adam and eve) are sinners

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Because multiplying by infinity is the equivalent of dividing by 0

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